7/12 每日一題(檢查字串是否由子字串組成)
Given a string s, check if it can be constructed by taking a substring of it and appending multiple copies of the substring together.
Example 1:
Input: s = "abab" Output: true Explanation: It is the substring "ab" twice.
Example 2:
Input: s = "aba" Output: false
Example 3:
Input: s = "abcabcabcabc" Output: true Explanation: It is the substring "abc" four times or the substring "abcabc" twice.
Constraints:
1 <= s.length <= 104sconsists of lowercase English letters.
class Solution:
def repeatedSubstringPattern(self, s: str) -> bool:
if len(s)==1:
return False
i=0
while i < len(s)//2:
p=s[0:i+1]
n=len(s)//len(p)
if p*n == s:
return True
i+=1
return False
標籤: leetcode

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