7/4 每日一題(根據LED亮的燈泡顯示時間)

 A binary watch has 4 LEDs on the top to represent the hours (0-11), and 6 LEDs on the bottom to represent the minutes (0-59). Each LED represents a zero or one, with the least significant bit on the right.

• For example, the below binary watch reads "4:51".

Given an integer turnedOn which represents the number of LEDs that are currently on (ignoring the PM), return all possible times the watch could represent. You may return the answer in any order.

The hour must not contain a leading zero.

• For example, "01:00" is not valid. It should be "1:00".

The minute must be consist of two digits and may contain a leading zero.

• For example, "10:2" is not valid. It should be "10:02".

 

Example 1:

Input: turnedOn = 1
Output: ["0:01","0:02","0:04","0:08","0:16","0:32","1:00","2:00","4:00","8:00"]

Example 2:

Input: turnedOn = 9
Output: []

 

Constraints:

• 0 <= turnedOn <= 10

from itertools import combinations

class My_watch:

    def __init__(self):

        '''12小時制'''

        self.h=[8,4,2,1]

        self.m=['32','16','8','4','2','1']

        self.h.extend(self.m)

       

       

    def on(self,turnedOn):

        time_list=[]

        if turnedOn == 0:

            return ['0:00']        

       

        comb_time=list(combinations(self.h,turnedOn))

            #亮起n個LED的所有組合

        for i in comb_time:

            count_h=0 #初始化小時

            count_m=0 #初始化分鐘

           

            for j in i:

                if isinstance(j,int): #如果是整數就表示他是小時的元素

                    count_h += j

                if isinstance(j,str): #如果是字串就表示他是分鐘的元素

                    count_m +=int(j)

            if count_h <=12 and count_m <=60:  #12小時制

                time=str(count_h)+":"+str(count_m).zfill(2)

                time_list.append(time)

        return time_list