9/18 每日一題(檢查矩形是否重疊)
An axis-aligned rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) is the coordinate of its bottom-left corner, and (x2, y2) is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.
Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.
Given two axis-aligned rectangles rec1 and rec2, return true if they overlap, otherwise return false.
Example 1:
Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3] Output: true
Example 2:
Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1] Output: false
Example 3:
Input: rec1 = [0,0,1,1], rec2 = [2,2,3,3] Output: false
Constraints:
rec1.length == 4rec2.length == 4-109 <= rec1[i], rec2[i] <= 109rec1andrec2represent a valid rectangle with a non-zero area.
class Solution:
def isRectangleOverlap(self, rec1: List[int], rec2: List[int]) -> bool:
x1,x2=rec1[0],rec1[2]
y1,y2=rec1[1],rec1[3]
if rec2[0]<x1 <rec2[2] or rec2[0] < x2 <rec2[2] or x1 < rec2[0] < x2 or x1 < rec2[2] < x2:
print(f'x對')
if rec2[1]<y1<rec2[3] or rec2[1] < y2 <rec2[3] or y1 <rec2[1] <y2:
return True
return False
檢查 x,y 矩形的邊界 是否有重疊
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class Solution:
def isRectangleOverlap(self, rec1: List[int], rec2: List[int]) -> bool:
X_overlab=not(rec1[2]<=rec2[0] or rec2[2]<=rec1[0])
Y_overlab=not(rec1[3]<=rec2[1] or rec2[3]<=rec1[1])
return (X_overlab and Y_overlab)標籤: leetcode

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