9/4 每日一題(MYSQL 列出以'DIAB1'當前綴詞的資料)

 Table: Patients

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| patient_id   | int     |
| patient_name | varchar |
| conditions   | varchar |
+--------------+---------+
patient_id is the primary key (column with unique values) for this table.
'conditions' contains 0 or more code separated by spaces. 
This table contains information of the patients in the hospital.

 

Write a solution to find the patient_id, patient_name, and conditions of the patients who have Type I Diabetes. Type I Diabetes always starts with DIAB1 prefix.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Patients table:
+------------+--------------+--------------+
| patient_id | patient_name | conditions   |
+------------+--------------+--------------+
| 1          | Daniel       | YFEV COUGH   |
| 2          | Alice        |              |
| 3          | Bob          | DIAB100 MYOP |
| 4          | George       | ACNE DIAB100 |
| 5          | Alain        | DIAB201      |
+------------+--------------+--------------+
Output: 
+------------+--------------+--------------+
| patient_id | patient_name | conditions   |
+------------+--------------+--------------+
| 3          | Bob          | DIAB100 MYOP |
| 4          | George       | ACNE DIAB100 | 
+------------+--------------+--------------+
Explanation: Bob and George both have a condition that starts with DIAB1.

# Write your MySQL query statement below

SELECT * FROM Patients

WHERE conditions LIKE 'DIAB1%' or conditions LIKE '% DIAB1%'

#篩選條件為 conditions = DIAB1XXXXXX 或者是 conditions = XXXXX DIAB1XXXXX

-------------------------

# Write your MySQL query statement below
select patient_id, patient_name, conditions from patients
where conditions like 'DIAB1%'

union

select patient_id, patient_name, conditions from patients
where conditions like '% DIAB1%'