9/5 每日一題(調用提供API 使用二分法)
We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.
You call a pre-defined API int guess(int num), which returns three possible results:
-1: Your guess is higher than the number I picked (i.e.num > pick).1: Your guess is lower than the number I picked (i.e.num < pick).0: your guess is equal to the number I picked (i.e.num == pick).
Return the number that I picked.
Example 1:
Input: n = 10, pick = 6 Output: 6
Example 2:
Input: n = 1, pick = 1 Output: 1
Example 3:
Input: n = 2, pick = 1 Output: 1
Constraints:
1 <= n <= 231 - 11 <= pick <= n
# The guess API is already defined for you.
# @param num, your guess
# @return -1 if num is higher than the picked number
# 1 if num is lower than the picked number
# otherwise return 0
# def guess(num: int) -> int:
class Solution:
def guessNumber(self, n: int) -> int:
left=1
right=n
while left <= right:
mid = left +(right-left)//2
if guess(mid)==0:
return mid
elif guess(mid) == 1:
#還要更大
left=mid+1
else:
#還要更小
right=mid-1
---------------------------------
# The guess API is already defined for you.
# @param num, your guess
# @return -1 if num is higher than the picked number
# 1 if num is lower than the picked number
# otherwise return 0
# def guess(num: int) -> int:
class Solution:
def guessNumber(self, n: int) -> int:
L, R = 1, n
while L <= R:
print(L, R)
M = (L + R) // 2
if guess(M) == 1:
L = M + 1
elif guess(M) == -1:
R = M - 1
else:
return M
return 0標籤: leetcode

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