10/14 每日一題(檢查是重複輸入就通過, 雙指針)

Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

 

Example 1:

Input: name = "alex", typed = "aaleex"
Output: true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:

Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: 'e' must have been pressed twice, but it was not in the typed output.

 

Constraints:

• 1 <= name.length, typed.length <= 1000
• name and typed consist of only lowercase English letters.

 

class Solution:

    def isLongPressedName(self, name: str, typed: str) -> bool:

        '檢查相對位置, 雙指針'

        l,r=0,0

        n1,n2=len(name),len(typed)

        while r < n2:

            if l < n1 and name[l] == typed[r]:

                l+=1

                r+=1

            elif r>0 and typed[r]==typed[r-1]:

                r+=1

            else:

                #出現不重複字元#       

                # print(f'l={l},r={r}')

                return False

       

        return l==n1